Nice! I'd use Number constructor for this particular case. ['1', '7', '11'].map(Number)

Why ['1', '7', '11'].map(parseInt) returns [1, NaN, 3] in Javascript
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Eric Tong
Eduardo Ottaviani Aragão
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Nov 16, 2020
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Nice! I'd use Number constructor for this particular case. ['1', '7', '11'].map(Number)
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Written by Eduardo Ottaviani Aragão120 Followers
·114 Following
Javascript Programmer
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